Show DevBest [PHP] Simple File Directory Scanner

[Markshall]

I've been wanting to do one of these for some time as I find them very handy.

Basically, this function I've created allows you to get files from any directory on your webserver.

The code can be found below:

<?php
function GetFiles( $directory, $output_array = false, $exts = array( "png", "jpeg", "jpg", "bmp", "gif" ) )
{
    if ( is_dir( $directory ) )
    {
        $scan   = scandir( $directory );
        $return = array();
        foreach( $scan as $file )
        {
            $ext = strtolower( end( explode( ".", $file ) ) );
            if ( $file !== "." && $file !== ".." & in_array( $ext, $exts ) == true )
            {
                if ( $output_array == true )
                {
                    $return[] = $file;
                }
                else
                {
                    echo $file . "<br />";
                }
            }
        }
        if ( $output_array == true ) return $return;
    }
    else
    {
        echo "Directory {$directory} is invalid!";
    }
}
 
GetFiles( "images/work" );
?>

The code above will return something similar to this:

<?php
function GetFiles( $directory, $output_array = false, $exts = array( "png", "jpeg", "jpg", "bmp", "gif" ) )
{
    if ( is_dir( $directory ) )
    {
        $scan   = scandir( $directory );
        $return = array();
        foreach( $scan as $file )
        {
            $ext = strtolower( end( explode( ".", $file ) ) );
            if ( $file !== "." && $file !== ".." & in_array( $ext, $exts ) == true )
            {
                if ( $output_array == true )
                {
                    $return[] = $file;
                }
                else
                {
                    echo $file . "<br />";
                }
            }
        }
        if ( $output_array == true ) return $return;
    }
    else
    {
        echo "Directory {$directory} is invalid!";
    }
}
 
echo "<pre>";
print_r ( GetFiles( "images/work", true ) );
echo "</pre>";
?>

The code above will return something similar to:

You can make the function return an array by adding ", true" after your directory.

Hope this script helps.

m0nsta.

 

[At0m]

Wow, nice code m0nsta, great job
This will help me to undestand more PHP.
Keep going.

 

[Markshall]

No worries hope it helps

 

[Kryptos]

Nice, nice!

I know another way of doing something like that ;P

function getFiles($dir)
{
    foreach(glob($dir) as $file)
    {
          echo $file; //Just echo it, edit it and make it do whatever you want
    }
}

So you could do...

getFiles('images/*.png'); //Get all PNG files in the directory
getFiles('images/*.jpg'); //Get all JPG files in the directory
getFiles('images/*'); //Get all files in the directory
getFiles('images/*.txt'); //Get all TXT files in the directory

Should work, I probably have a typo there. Me + DevBest Post Form + Programming === typo/bad

 

[Markshall]

Nice, I didn't know you could do that - you learn something new everyday!

And as for typos, yes -- you put 'funtion' and not 'function'

 

[Sledmore]

You don't know how much I love you for this, I tried something ages ago for my roleplay hotel, like this, but the code was a little crap xD, I'll try this out thanks for it, ;D.

 

[Markshall]

You don't know how much I love you for this, I tried something ages ago for my roleplay hotel, like this, but the code was a little crap xD, I'll try this out thanks for it, ;D.

No worries Sledmore !!