$_GET Help!

NSA

sudo apt-get thefuckout.tar.gz
Dec 9, 2011
715
86
Hey guys,

Doing a project for College and I need to be able to display information from a database.
I currently have a profile.php page which set's some variables, send's them to another PHP file which acts as a CSS file.
The problem I am having is, it doesn't update unless I "refresh the page". If I go directly to the url profile.php?id=Josh it will still display for instance Anna's username from "profile.php?id=anna". But when I refresh the new one, it updates to "Josh".

I am aware of security issues in my code, but it is just for a College project, so don't bawl on at me about security.

Code:
Code:
<?php
$_SESSION['localhostrealname'] = "";
include("ban.php");
session_start();
$id = $_SESSION['localhostid'];
$con = mysql_connect("localhost","root","");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }
 
mysql_select_db("vote", $con);
 
$result = mysql_query("SELECT * FROM layout WHERE username='$id'");
 
while($row = mysql_fetch_array($result))
  {
  $background = $row['background'];
  $profile_picture = $row['profile_picture'];
  $real_name = $row['real_name'];
  $_SESSION['localhostrealname'] = "$real_name";
  }
 
mysql_close($con);
?>
<link rel='stylesheet' type='text/css' href='back.php' />
<div id="profile_picture">
 
</div>
<?php
$id = $_GET['id'];
$_SESSION['localhostid'] = "$id";
?>
<span id="real_name"><?php echo $_SESSION['localhostrealname']; ?></span>
 

NSA

sudo apt-get thefuckout.tar.gz
Dec 9, 2011
715
86
Warning: session_destroy(): Trying to destroy uninitialized session in F:\xampp-portable\htdocs\profile.php on line 2
 

NSA

sudo apt-get thefuckout.tar.gz
Dec 9, 2011
715
86
The script will get the ID from the URL and put it into localhostid then it will get the users real name with that ID and fetch it, and display it on the webpage.
 

Weasel

👄 I'd intercept me
Nov 25, 2011
4,132
2,456
PHP:
<?php
session_start();
include("ban.php");
 
$userid = $_GET['id'];
 
$con = mysql_connect("localhost","root","");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }
 
mysql_select_db("vote", $con);
 
$result = mysql_query("SELECT * FROM layout WHERE username='".$userid."' ");
 
while($row = mysql_fetch_array($result))
  {
  $background = $row['background'];
  $profile_picture = $row['profile_picture'];
  $real_name = $row['real_name'];
  }
 
mysql_close($con);
?>
<link rel='stylesheet' type='text/css' href='back.php' />
<div id="profile_picture">
 
</div>
<span id="real_name"><?php echo $real_name; ?></span>
 

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