Does this look alright?

[Integers]

<?php
include 'core/init.php';
 
if (user_exists('James') === true) {
echo 'This exists';
}
die();
 
if (empty($_POST) === false) {
$username = $_POST['username'];
$password = $_POST['password'];
 
if (empty($username) === true || empty($password) === true) {
$errors[] = 'Please enter a username and password';
} else if (user_exists($username) === false) {
$errors[] = 'Username/Password not found!';
}
}
?>

Does this look alright

 

[RastaLulz]

No, your code will always end before the other two if's are ever executed.

 

[Integers]

Sorry but you can post the updated code I don't get what you mean

 

[RastaLulz]

You're calling the "die()" function right after the first "if", meaning that PHP will end right there.

 

[Integers]

Still doesn't work :/

Edit: maybe its this?

<?php
function user_exists($username) {
$username = sanitize($username);
$query = mysql_query("SELECT COUNT (`id`) FROM `users` WHERE `username` = '$username'");
return (mysql_result($query, 0) == 1) ? true : false;
}
?>

 

[Gajeel]

<?phpinclude 'core/init.php';

if (user_exists('James') === true) {
echo 'This exists';
};

if (empty($_POST) === false) {$username = $_POST['username'];$password = $_POST['password'];

if (empty($username) === true || empty($password) === true) {$errors[] = 'Please enter a username and password';
} else if (user_exists($username) === false) {$errors[] = 'Username/Password not found!';
}
die()}?>

I think he mean you must execute die at the end instead of the first, since it won't execute the next statements if the die goes after the first if statement?justtryingtohelp.

 

[Integers]

fixed but thanks