PHP Array with Javascript and variable label id

Skythrust

Skythrust

Member
Jul 9, 2019
133
7
Hi there!

I am learning again new stuff, and I am trying to find a solution to use a JSON Array with JavaScript/variable label id.

every record in the array does have an icon value (for example 1,2 or 3), First text and a second text. Every record does need his own label id value to use this code below.

I have searched a long time on the internet, but I got stucked in the codes, and I have no idea where I need to start :-(. the following step is to change the JSON array directly to a SQL Server Database.

JSON Array:
JSON: 
$json = '[{"Id":"1","Icon":"1","FName":"Facebook","Sname":"ThisPasswordIsSecret"},{"Id":"2","Icon":"2","FName":"Instagram","Sname":"ThisPasswordIsSecret"},{"Id":"7","Icon":"3","FName":"Twitter","Sname":"ThisPasswordIsSecret"},]';

PHP Code (plain HTML)
HTML: 
<body>
        <div class="flip">
            <div class="card">
                <div class="face front">
                    <img src="IMAGEID" />
                    <div class="label" id="label">Facebook</div>
                    <button class="viewbtn" onclick="changeLabel()">&#128275;</button>
                </div>
            </div>
        </div>   
    </body>
</html>

<script>
    function changeLabel() {
        let label = document.getElementById('label');
        label.innerText = "ThisPasswordIsSecret";
        setTimeout(function(){ document.getElementById("label").innerHTML = 'Facebook';}, 3000);
        
    }
    
</script>

Thanks in advance!
Post automatically merged:

I have found the way for the class id, only now is the script left. I was assuming that I could realize this on this way. But it doesn't work.

Code: 
<?php

$json = '[{"Id":"1","Icon":"1","FName":"Facebook","Sname":"ThisPasswordIsSecret"},{"Id":"2","Icon":"2","FName":"Instagram","Sname":"ThisPasswordIsSecret"},{"Id":"7","Icon":"3","FName":"Twitter","Sname":"ThisPasswordIsSecret"}]';
$array = json_decode($json, true);

?>

<?php foreach ($array as $record) { ?>
        <div class="flip">
            <div class="card">
                <div class="face front">
                    <img src="https://lh3.googleusercontent.com/XDScQo39jp9nk8kzAY_GOGYkb999mmMIqQGacISVnkGNc-tnZDZ1lD4valDhPOz7wxTm3pgk=s50-h50-e365" />
                    <div class="label2" id="<?php echo "label".$record['Id']; ?>"><?php echo $record['FName']; ?></div>
                    <button class="viewbtn" onclick="changeLabel()">&#128275;</button>
                </div>
            </div>
        </div>   
        
<script>
    function changeLabel() {
        let label = document.getElementById('<?php echo 'label'.$record['Id']; ?>');
        label.innerText = "test";
        setTimeout(function(){ document.getElementById('<?php echo 'label'.$record['Id']; ?>').innerHTML = 'Works';}, 3000);
        
    }
    
</script>

        <?php } ?>
 
Last edited:
Sort by date Sort by votes
Markshall

Markshall

Русский Стандарт
Contributor
Dec 18, 2010
2,637
2,389
You’re redeclaring changeLabel() over and over, so the ID inside is going to be the same for each record.

You have 2 options; either declare one function and allow and ID parameter to be passed in, or change the name of the function for each record.

Option 1: pass an ID to the function (recommended)
PHP: 
<?php

$json = '[{"Id":"1","Icon":"1","FName":"Facebook","Sname":"ThisPasswordIsSecret"},{"Id":"2","Icon":"2","FName":"Instagram","Sname":"ThisPasswordIsSecret"},{"Id":"7","Icon":"3","FName":"Twitter","Sname":"ThisPasswordIsSecret"}]';
$array = json_decode($json, true);

?>

<?php foreach ($array as $record) { ?>
        <div class="flip">
            <div class="card">
                <div class="face front">
                    <img src="https://lh3.googleusercontent.com/XDScQo39jp9nk8kzAY_GOGYkb999mmMIqQGacISVnkGNc-tnZDZ1lD4valDhPOz7wxTm3pgk=s50-h50-e365" />
                    <div class="label2" id="<?php echo "label".$record['Id']; ?>"><?php echo $record['FName']; ?></div>
                    <button class="viewbtn" onclick="changeLabel('<?php echo $record['Id']; ?>')">&#128275;</button>
                </div>
            </div>
        </div>   
        

        <?php } ?>
<script>
    function changeLabel(id) {
        let label = document.getElementById(`label${id}`);
        label.innerText = "test";
        setTimeout(function(){ document.getElementById(`label${id}`).innerHTML = 'Works';}, 3000);
        
    }
    
</script>

Option 2: create a new function each time
PHP: 
<?php

$json = '[{"Id":"1","Icon":"1","FName":"Facebook","Sname":"ThisPasswordIsSecret"},{"Id":"2","Icon":"2","FName":"Instagram","Sname":"ThisPasswordIsSecret"},{"Id":"7","Icon":"3","FName":"Twitter","Sname":"ThisPasswordIsSecret"}]';
$array = json_decode($json, true);

?>

<?php foreach ($array as $record) { ?>
        <div class="flip">
            <div class="card">
                <div class="face front">
                    <img src="https://lh3.googleusercontent.com/XDScQo39jp9nk8kzAY_GOGYkb999mmMIqQGacISVnkGNc-tnZDZ1lD4valDhPOz7wxTm3pgk=s50-h50-e365" />
                    <div class="label2" id="<?php echo "label".$record['Id']; ?>"><?php echo $record['FName']; ?></div>
                    <button class="viewbtn" onclick="changeLabel<?php echo $record['Id']; ?>()">&#128275;</button>
                </div>
            </div>
        </div>   
        
<script>
    function changeLabel<?php echo $record['Id']; ?>() {
        let label = document.getElementById('<?php echo 'label'.$record['Id']; ?>');
        label.innerText = "test";
        setTimeout(function(){ document.getElementById('<?php echo 'label'.$record['Id']; ?>').innerHTML = 'Works';}, 3000);
        
    }
    
</script>

        <?php } ?>

I typed this on my phone so it may be wrong.[/B]
 
Upvote 0 Downvote

Users who are viewing this thread

Total: 2 (members: 0, guests: 2)
☀️  Switch to Light Theme

Latest posts

Top